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When is a parallelogram a rectangle?

Now that Detective Reese understood how to prove if statements, he was ready to prove that a parallelogram is a rectangle if and only if its diagonals are congruent. Reese knew he had to prove these two statements:

  1. If a parallelogram is a rectangle, then the diagonals are congruent.
  2. If a parallelogram has congruent diagonals, then its a rectangle.

Read tabs 1 and 2 to see how Reese proved each statement. Then, go to the matching activity below to create your own proof.

Proof 1

Proof 2

Parallelogram

Given: Parallelogram ABCD is a rectangle.

Prove: AC = BD.

Proof

Consider triangles △BAD and △CDA.
Opposite sides of a rectangle are congruent. Therefore, by definition of rectangle, AB = CD.
By the definition of identity, AD = AD.
All vertices of a rectangle are right angles. Therefore, by definition of rectangle, ∠BAD = ∠CDA.
By side-angle-side (SAS), △BAD \(\mathsf{ \cong }\) △CDA.
By CPCTC, AC = BD.

Parallelogram

Given: AC = BD.

Prove: Parallelogram ABCD is a rectangle.

Proof

Consider triangles △ABD and △ADC.
By definition of parallelogram, AB = CD.
By the definition of identity, AD = AD.
By the given information, AC = BD.
By side-side-side (SSS), △ABD \(\mathsf{ \cong }\) △ADC
By CPCTC, ∠BAD = ∠ADC.
By definition of parallelogram, ∠BAD and ∠ADC are also supplementary.
Therefore, ∠BAD = ∠ADC = 90° because they are equal and supplementary.
Now consider triangles △ABC and △DCB.
By SSS, △ABC \(\mathsf{ \cong }\) △DCB.
By definitions of congruent triangles and parallelogram, ∠ABC = ∠DCB = 90° because they are equal and supplementary.
Hence, parallelogram ABCD has four right angles.
Therefore, ABCD is a rectangle.

Parallelogram

Parallelogram QRST is a rectangle. Prove QS = RT by matching the statements below to the correct reasons for each statement.

QR = ST

QT = QT

∠RQT = ∠STQ

△RQT ≅ △STQ

QS = RT

Opposite sides of a rectangle are congruent.

By SAS.

All vertices of a rectangle are right angles.

By CPCTC.

Identity


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