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How is mass conserved during a chemical reaction?

Recall that the law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. This means that when a chemical reaction occurs and something new is created, the mass of the final product(s) must be equal to the mass of the original reactant(s). In other words:

Mass of reactants = Mass of products

A detailed description of this image follows in the next paragraph.

In this example, you can see that the total mass of the reactants (CaCl2 and Na2SO4) before the reaction occurs was 184.34 grams. When they are mixed, a chemical reaction occurs and forms the products (CaSO4 and NaCl), which have a total mass of 184.34 grams. Notice that this is the same as the mass of the reactants.

Let's Practice

Practice applying the law of conservation of mass to chemical reactions by completing this activity. Answer the question on each tab, then check your answer.

What mass of rust (Fe2O3) will be produced when 25.5 grams of iron reacts with 11.0 grams of oxygen?

4Fe+3O22Fe2O3

36.5 g of Fe2O3

If you need help arriving at this answer, click the Solution button.

Step 1: Write an equation showing conservation of mass of reactants and products.

Mass of reactants = Mass of products

Mass of Fe + Mass of O2= Mass of Fe2O3

Step 2: Substitute known values into the equation and solve for the unknown value.

Mass of Fe + Mass of O2= Mass of Fe2O3

25.5 g+11.0 g= Mass of Fe2O3

36.5 g= Mass of Fe2O3

How many grams of table salt will be formed when 6.4 g of sodium metal reacts with 9.9 g of chlorine gas?

2Na+Cl22NaCl

16.3 g of NaCl

If you need help arriving at this answer, click the Solution button.

Step 1: Write an equation showing conservation of mass of reactants and products.

Mass of reactants = Mass of products

Mass of Na + Mass of Cl2= Mass of NaCl

Step 2: Substitute known values into the equation and solve for the unknown value.

Mass of Na + Mass of Cl2= Mass of NaCl

6.4 g+9.9 g= Mass of NaCl

16.3 g= Mass of NaCl

A plant takes in 21.3 grams of carbon dioxide and 8.7 grams of water. If it produces 14.5 grams of glucose, how much oxygen gas is also produced?

6CO2+6H2OC6H12O6+6O2

15.5 g of O2

If you need help arriving at this answer, click the Solution button.

Step 1: Write an equation showing conservation of mass of reactants and products.

Mass of reactants = Mass of products

Mass of CO2 + Mass of H2O= Mass of C6H12O6 + Mass of 6O2

Step 2: Substitute known values into the equation and solve for the unknown value.

Mass of CO2 + Mass of H2O= Mass of C6H12O6 + Mass of 6O2

21.3 g+8.7 g=14.5 g + Mass of 6O2

30.0 g=14.5 g + Mass of 6O2

30.0 g14.5 g= Mass of 6O2

15.5 g= Mass of 6O2