Zoo Multiplication

Caleb is visiting the zoo today! Let’s help him count animals using multiplication strategies.

This is the alligator exhibit. How many alligators do you see, Caleb? The sign says 6 times 8. Let’s help Caleb by finding the product using repeated addition.

To find 6 times 8, we need to add 8 six times. Do you know the sum? That’s right! The sum is 48. That means 6 times 8 equals 48.

There are 48 alligators!

Here are the cheetahs. If the sign says 9 times 6, how many cheetahs are in this exhibit? Let’s use a skip-counting sequence to find out!

We need to skip count by 6 nine times: 6, 12, 18, 24, 30, 36, 42, 48, 54. 54 is the 9th number in our sequence. That means 9 times 6 equals 54! That’s a lot of cheetahs!

Caleb is at the next exhibit. Look at all of the flamingos! How many do you see, Caleb? What is 10 times 9?

This number line is labeled with intervals of 9. Let’s make 10 jumps of 9 to find the product. Nice work! 10 times 9 equals 90.

There are 90 flamingoes in the flamingo exhibit!

Here are the kangaroos. Can you find the product of 7 times 7 using a multiplication table?

Find the factors on either side of the table. The 7s meet at the number 49. Ta da! 7 \({ \times }\) 7 = 49. There are 49 kangaroos!

This is the last exhibit Caleb will visit today. There are so many turtles! What is 10 times 10?

Let’s find the product using an array. We’ll need 10 rows made up of 10 dots. Wow, that’s a total of 100 dots! Caleb sees 100 turtles in the exhibit.

Thanks for helping Caleb multiply. He had a great time at the zoo!