Make sure you understand the material covered in this lesson by answering the multiple choice questions below, which are similar to the questions you'll see on this lesson's quiz. Use this figure to answer all the questions.
Which segments are diagonals of rectangle ABCD?
- BC and AD and BE
- BC and AD
- AC and BD and AE
- AC and BD
The diagonal is a line that connects opposite vertices, and a rectangle has two diagonals. The diagonals of rectangle ABCD are AC and BD.
The diagonal is a line that connects opposite vertices, and a rectangle has two diagonals. The diagonals of rectangle ABCD are AC and BD.
The diagonal is a line that connects opposite vertices, and a rectangle has two diagonals. The diagonals of rectangle ABCD are AC and BD.
The diagonal is a line that connects opposite vertices, and a rectangle has two diagonals. The diagonals of rectangle ABCD are AC and BD.
Which two segments are equal?
- AB = BC
- BD = BE
- AE = EC
- AC = AE
The diagonals bisect each other at point E. Therefore AE = EC.
The diagonals bisect each other at point E. Therefore AE = EC.
The diagonals bisect each other at point E. Therefore AE = EC.
The diagonals bisect each other at point E. Therefore AE = EC.
What is the area of △BDC?
- 48
- 24
- 8
- 10
BD= 2*5 = 10. Therefore AB = \(\mathsf{ \small\sqrt{10^{2}- 6^{2}}}\) = 8. The area of △BDC = \(\mathsf{ \small\frac{1}{2}}\)*b*h = \(\mathsf{ \small\frac{1}{2}}\)*6*8 = 24
BD= 2*5 = 10. Therefore AB = \(\mathsf{ \small\sqrt{10^{2}- 6^{2}}}\) = 8. The area of △BDC = \(\mathsf{ \small\frac{1}{2}}\)*b*h = \(\mathsf{ \small\frac{1}{2}}\)*6*8 = 24
BD= 2*5 = 10. Therefore AB = \(\mathsf{ \small\sqrt{10^{2}- 6^{2}}}\) = 8. The area of △BDC = \(\mathsf{ \small\frac{1}{2}}\)*b*h = \(\mathsf{ \small\frac{1}{2}}\)*6*8 = 24
BD= 2*5 = 10. Therefore AB = \(\mathsf{ \small\sqrt{10^{2}- 6^{2}}}\) = 8. The area of △BDC = \(\mathsf{ \small\frac{1}{2}}\)*b*h = \(\mathsf{ \small\frac{1}{2}}\)*6*8 = 24
What is the area of rectangle ABCD?
- 48
- 24
- 8
- 10
The area of rectangle ABCD is twice the area of △BDC, which is 2*24 = 48. Also, A = b*h = 6*8 = 48
The area of rectangle ABCD is twice the area of △BDC, which is 2*24 = 48. Also, A = b*h = 6*8 = 48
The area of rectangle ABCD is twice the area of △BDC, which is 2*24 = 48. Also, A = b*h = 6*8 = 48
The area of rectangle ABCD is twice the area of △BDC, which is 2*24 = 48. Also, A = b*h = 6*8 = 48
Summary
Questions answered correctly:
Questions answered incorrectly:
